修复了复制粘贴带子节点的节点时发生错误的问题

bower.json

@@ -2,7 +2,7 @@
     "name": "kityminder-core",
     "title": "Kity Minder Core",
     "description": "Powerful online mind graphic visualization and editor (command based)",
-    "version": "1.4.12",
+    "version": "1.4.13",
     "main": [
         "release/kityminder.core.min.js",
         "release/kityminder.core.css"

dist/kityminder.core.js

 /*!
  * ====================================================
- * kityminder - v1.4.1 - 2015-07-22
+ * kityminder - v1.4.1 - 2015-08-05
  * https://github.com/fex-team/kityminder-core
  * GitHub: https://github.com/fex-team/kityminder-core.git 
  * Copyright (c) 2015 Baidu FEX; Licensed MIT
@@ -4270,6 +4270,13 @@ _p[42] = {
                 var children = child.children.map(function(node) {
                     return node.clone();
                 });
+                /*
+            * fixed bug: Modified on 2015.08.05
+            * 原因：粘贴递归 append 时没有清空原来父节点的子节点，而父节点被复制的时候，是连同子节点一起复制过来的
+            * 解决办法：增加了下面这一行代码
+            * by: @zhangbobell zhangbobell@163.com
+            */
+                child.clearChildren();
                 for (var i = 0, ci; ci = children[i]; i++) {
                     appendChildNode(child, ci);
                 }

src/module/clipboard.js

@@ -20,6 +20,15 @@ define(function(require, exports, module) {
             var children = child.children.map(function(node) {
                 return node.clone();
             });
+
+            /*
+            * fixed bug: Modified on 2015.08.05
+            * 原因：粘贴递归 append 时没有清空原来父节点的子节点，而父节点被复制的时候，是连同子节点一起复制过来的
+            * 解决办法：增加了下面这一行代码
+            * by: @zhangbobell zhangbobell@163.com
+            */
+            child.clearChildren();
+
             for (var i = 0, ci;
                 (ci = children[i]); i++) {
                 appendChildNode(child, ci);